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(3(x-2)^2)/(6(x-2)^4)
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\[\frac{1}{2(x-2)^2}\]
= 3(x-2)(x+2) / 6(x-2)(x-2)(x+2)(x+2) = 1/2(x-2)(x+2) = 1/2(x-2)^2
I agree!
let the given expression be divided into two parts 3/6 * (x-2)^2/(x-2)^4 3/6 = 1/2 and (x-2)^2 = (x-2)(x-2) (x-2)^4 = (x-2)(x-2)(x-2)(x-2) \[3/6 * (x-2)^2/(x-2)^4\] \[(x-2)^2 = (x-2)(x-2) \] \[(x-2)^4 = (x-2)(x-2)(x-2)(x-2)\] hence \[[(x-2)(x-2)]/[(x-2)(x-2)(x-2)(x-2)]\] that is \[1/(x-2)(x-2)\] or \[1/(x-2)^2\] hence answer is \[1/[2 * (x-2)^2)]\]
good
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got it :)
thanks
r u indian
no
then ?
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