Question

given that 5 exponent -m is equal to x..find an expression in x, for 5 exponent 1+m..

Answer 1

\[5^{-m}\]

Answer 2

= x right

Answer 3

we have to find \[5^{m+1}\]

Answer 4

ok go on

Answer 5

ok see ,
5^(-m) = x
we have to find 5^(m+1)
according to laws of exponents
a^(b+c) = a^b * a^c
hence
5^(m+1) = 5^m * 5^1
= 5^m * 5
1/(5^m) = x
1/x = 5^m
5^m * 5 = 5^(m+1)
1/x * 5 = 5^(m+1)
5/x = 5^(m+1)

Answer 6

got it now agradecompetent

Answer 7

yeah

Answer 8

any other question ?

Answer 9

no
i solved all
or u wanna try them?

Answer 10

\[\color{indigo}{\text{yes of course i would try them :) may be i would be successful in them or not. let us see }}\]

Answer 11

given that {log base 8 (p+2)+log base 8q}=r and
{log base 2 (p-2)-log base 2q=2r+1,
show that p^2=4+2*32r

Answer 12

it is rather show that p^2=4+2*32^r