for a population of 800000 subway riders, the numbers of subway trips taken per rider last january are approximately normally distributed with a mean of 56 trips and a standard deviation of 13 trips. approximately how many of the riders took between 30 and 43 trips last january???
I hate statistics
me too studyn for my gre
ahhh, zscores, gotta love em
what do you have for computing, table or calculator?
table..and calc on my laptop
\[Z=\frac{x-\mu}{\sigma}\]
we wanna cram the non standard stuff into the normal curve
I neva seen that z formula before
ok
the zscore allows us to compare different amounts as tho they were equals
ok..
so lets start cramming it in :) mean = 56 30 - 56 = |-26| 43 - 56 = |-13| and sd = 13, were in luck, your numbers are divisable by 13 so its fairly simple
26/13 = 2, we are 2 standard deviations from the mean 13/13 = 1, we are 1 standard deviation from the mean the area between 1 and 2 is what we want to find
do you know the "empirical rule"?
ok...so the answers given are 60000 110000 160000 210000 270000
no explain empirical rule..
i got no idea what the answer is yet, I am going thru it along with you :)
the empirical rule is a rule of thumb for the area/probability under the curve for deviations from the mean of 1,2, and 3
1 = 68 2 = 95 3 = 99 but, we need only half of these since our sds are just on one side
2 - 1 will give us the approximate area 95/2 - 68/2 = N 95 -68 ---- 27 /2 = 13.5 right?
if so then our answer is: 800,000 * .135
.135 * 800000= 108000 looks close to 110000 thanks..
looks good to me, and it makes sense as well :) hope its right ;)
so situations like these i dont necessarily need to draw a bell curve diagam??
draw the curve, its good practice for later
and understand the z score / sds
zscore relates to standard deviations as: 1 zscore: 1 sd in this problem we are given an sd of 13 so thats a ration of; 1:13, or simply put 1/13 when the mean is at 0 we can equate the distance of any given data point from the mean by using this ratio. take for instance the data given here: mean = 56 and we have a distance of 30 away from it; 30 <---->56 -56 -56 ---- ----- -26 <----> 0 26 we simply shift it all to look at it at a mean of 0, and an sd of 1, so use our ratio now of 1/13 26*1z/13 = 26z/13 = 2z, we have a zscore of 2, or simply 2 sds away from the mean
not a "distance of 30" but rather we need to find the distance between 56 and 30 ....
ahhhh thankkkkks
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