Question

Can someone show me how to factor??? Here is the problem: 6z^4-24z^2

Answer 1

6z^2(z^2-4)

Answer 2

6z^2(z^2-4)
6z^2(z-2)(z+2)

Answer 3

take a common factor 6z^2

Answer 4

6z^4-24z^2

6z^2 is common so,

6z^2(z^2-4)
6z^2(z-2)(z+2)

Answer 5

then
6z^2(z^2-4) = 6z^2(z-2)(z+2)

Answer 6

okay and why do you have to put (z-2)(z+2)?

Answer 7

at the end?

Answer 8

because you have to factor \[z^2-4\]

Answer 9

factoring and multiplying are two sides of the same coin

Answer 10

for example:

3 * 4 = 12

12 is the product of 3 and 4

3 and 4 are factors of 12

Answer 11

i see and if it was z^2+4 at the you would have to put (z+2)(z+2)? right?

Answer 12

youre trying to make a pattern; that is not how you factor

Answer 13

z^2 + 4 doesnt factor across the "real" nukbers

Answer 14

or numbers even ....

Answer 15

there are some patterns that emerge, but they are not universal in their applications

Answer 16

the difference of 2 squares factors into conjugates

Answer 17

(a^2 - b^2) = (a+b)(a-b)

Answer 18

the sum of 2 squares does not factor like that

Answer 19

oh nvm...how would you factor 49x^2-81?

Answer 20

notice that it is a difference of 2 squares, and follow the pattern for it :)

Answer 21

(49x^2 - 81)

[(7x)^2 - 9^2] = (7x-9)(7x+9)

Answer 22

okay i think i'm starting to understand, but please please please PLEASE stay in case i need more help.

Answer 23

i got class starting real soon so i cant make any promises

Answer 24

okay you can go to class., i got it! =D

Answer 25

thank you for your help:)