Question

Help please... Given the equation:
Ca3(PO4)2+ 6 NaBr= 3CaBr + 2 Na3PO4
^H= +454 kJ
if 669 kJ of heat are involved in the reaction, how much CaBr2 was produced?

Answer 1

i got 4.42 moles of CaBr2, but can anyone confirm?

Answer 2

for each 454KJ of energy 3 moles of CaBr2 is produced .Then for each 1KJ of energy
3/454 moles are produced .So a total energy of 669KJ would produce (3/454)*669
moles = 4.42 moles

Answer 3

thank-you so much(: this explaination really helped!