Question

solve equation using sqrt property. express radicals in simplest form:
4-3x=33/(4-3x)

Answer 1

\[4-3x = \frac{33}{4-3x}\]

Answer 2

\[(4-3x)^2 = 33\]

Answer 3

\[4-3x = \sqrt{33}\]

Answer 4

You can solve for x from there

Answer 5

so...
(sqrt(33)-4)/-3
does that look right?

Answer 6

Yes

Answer 7

so since I need a positive and a negative answer, will the second one be:
(sqrt(33)+4)/-3
or does the negative 3 turn into a positive 3?

Answer 8

put +/- sqrt{33}

Answer 9

sry, I don't quite follow...

Answer 10

\[x = \frac{\pm \sqrt{33}-4}{-3}\]

Answer 11

nevermind, I got it. the 3 wasn't negative on either side. oh well.

Answer 12

thank you though!!

Answer 13

What do you mean it wasn't negative on either side?

Answer 14

answer was:
(4-sqrt33)/3, (4+sqrt33)/3

Answer 15

It's the same answer

Answer 16

I guess the system is picky

Answer 17

If I had just posted what x was, you may have gotten it. I didn't know what form they wanted the answer in. Online tests are stupid.

Answer 18

lol