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do you use calculus or precalulus to find the distance traveled in 15 sec by an object traveling at a constant velocity of 20 ft/sec
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" constant velocity " you don't need calculus
ok so how would i solve it?
you can if you wanna
20 ft each sec; for 15 secs ....
20+20+20+20+20+20+20+20+20+20+20+20+20+20+20
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or 15(20) :)
\[\frac{dv}{dt} = 20\] \[dv = 20dt\] \[\int dv =\int_{0}^{t} 20dt\] \[v=20t|^{t}\text{ ; at t = 15}\] \[v=20(15)-20(0)\]
im trying to find the distance traveled not the velocity
i know, and i did it 2 ways
you "can" use calculus to solve it, but its rather easy to just do the normal stuff
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20 feet per sec for 15 seconds is .... 20 * 15, feet
ohh because distance=rate times time?
yes
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