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Mathematics 18 Online
OpenStudy (anonymous):

do you use calculus or precalulus to find the distance traveled in 15 sec by an object traveling at a constant velocity of 20 ft/sec

OpenStudy (anonymous):

" constant velocity " you don't need calculus

OpenStudy (anonymous):

ok so how would i solve it?

OpenStudy (amistre64):

you can if you wanna

OpenStudy (amistre64):

20 ft each sec; for 15 secs ....

OpenStudy (amistre64):

20+20+20+20+20+20+20+20+20+20+20+20+20+20+20

OpenStudy (amistre64):

or 15(20) :)

OpenStudy (amistre64):

\[\frac{dv}{dt} = 20\] \[dv = 20dt\] \[\int dv =\int_{0}^{t} 20dt\] \[v=20t|^{t}\text{ ; at t = 15}\] \[v=20(15)-20(0)\]

OpenStudy (anonymous):

im trying to find the distance traveled not the velocity

OpenStudy (amistre64):

i know, and i did it 2 ways

OpenStudy (amistre64):

you "can" use calculus to solve it, but its rather easy to just do the normal stuff

OpenStudy (amistre64):

20 feet per sec for 15 seconds is .... 20 * 15, feet

OpenStudy (anonymous):

ohh because distance=rate times time?

OpenStudy (amistre64):

yes

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