Question

identify the oblique asymtote of f(x)=x^2+6x-9/x-2

Answer 1

no oblique asymptote can be found but found a vertical one :D

Answer 2

P(x) = Q(x) + R(x), such that asymptote = Q(x)

Answer 3

divide it thru and toss your remainder

Answer 4

x+8 <-- asymptote
------------
x-2 | x^2+6x-9
-x^2+2x
-------
8x -9
-8x+16
---------
7 , toss the 7

Answer 5

Thank you!!! :)

Answer 6

youre welcome

Answer 7

toss the 7 where?

Answer 8

i would put it in the garbage can
i wouldn't litter like amistre would

Answer 9

7 up?

Answer 10

I was a bit confused about the toss the 7 part.

Answer 11

the 7 part is a remainder that can be placed in at the end like this:

\[\frac{7}{x-2}\]
now, when x gets very large ... we are going towards infinity here .... this part goes eventually gets so small that it equals 0

Answer 12

so we can ignore it as part of the asymptote

Answer 13

so would the answer be -8x+16/7(x-2)?

Answer 14

no, the asymptote line that it approaches is: x+8

when x = infinity, then we can talk about it touching the asymptote

Answer 15

think of an asymptote as a line that the graph snuggles up to, but never touches

Answer 16

it gets closer and closer, but never hits it unless we can find an end to infinity

Answer 17

in other words, out there in the far off distance, that remainder part is useless and disappears into eternity