How do you complete the square to solve a quadratic equation?
first understand what a square is :)
given an equation like: x^2 + 6x + ___ what do we do to "complete the square"? \begin{array}c &&&(6/2)x\\ &x^2&x&x&x\\ &x\\ (6/2)x&x\\ &x\\ \end{array} how many parts do we nee to fill in to make a "complete square? \begin{array}c &&&(6/2)x\\ &x^2&x&x&x\\ &x&1&2&3\\ (6/2)x&x&4&5&6\\ &x&7&8&9\\ \end{array} 9 parts :) x^2 + 6x + 9 is a complete square
this is fun for simple geometric equivalences, but can get messy, so we simply stick the the algebra given an equation: ax^2 +bx + ___ we can "complete the square" by adding (b/2)^2 to it
x^2 + 4x + ___ (4/2)^2 = 2^2 = 4 x^2 + 4x + 4 is a complete square
x^2 - 5x + ____ (5/2)^2 = 25/4 x^2 - 5x + 25/4 is a complete square
once you know a complete square, it can be compressed, or compacted. x^2 + bx + (b/2)^2 = (x+(b/2))^2
Thanks amistre64. I'm 69 years old and brushing up on precalc/calc to help my 16 year old daughter. I asked the question to see if this forum really works, but your answer also helps me REMEMBER how to do the algebra here. Thanks again.
youre welcome, im abt 40 and still brushing up :)
there is a hodgepodge of answerers here, and if you need an indepth answer, dont be afraid to ask
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