Question

Algebraic Expressions Review.. leave answers in factored form.

(x+2)/(x-1)-2/(x+6)-14/(x^2+5x-6)

The answer given is x/(x-1).

I don't understand how to get that, though.

Answer 1

one request please write it with equation forum

Answer 2

\[\frac{x+2}{x-1}\] - \[\frac{2}{x+6}\] - \[\frac{14}{x^2+5x-6}\]

Answer 3

k

Answer 4

i got (x^2+6x)/(x^2 + 5x-6) that can be written as x/(x-1) in simplest form .

Answer 5

do u want process ?

Answer 6

But, I don't understand how you get that
yes please

Answer 7

ok , see here let me take first of all the first two terms that are : (x+2)/(x-1) - 2/(x+6)
now we have to first of all solve this :
LCM of (x-1)(x-6) = (x-1)*(x-6)
now u can easily solve this :
\[[(x+2)(x+6)-2(-1)]\div[(x-1)(x+6)] \]
u would get:
\[(x^2 + 6x + 14)\div(x^2+5x-6) \]

Answer 8

now we have this expression \[(x^2+6x+14)/(x^2+5x-6)\] and the other one : \[(14)/(x^2+5x-6)\]
\[(x^2+6x+14)/(x^2+5x-6) - (14)/(x^2+5x-6)\]
since denominators are same hence we can write it like this:
\[{(x^2+6x+14-14)} / (x^2+5x-6)\]

that is
\[(x^2+6x)/(x^2+5x-6)\]

Answer 9

now we have this expression \[(x^2+6x+14)/(x^2+5x-6)\] and the other one : \[(14)/(x^2+5x-6)\]
\[(x^2+6x+14)/(x^2+5x-6) - (14)/(x^2+5x-6)\]
since denominators are same hence we can write it like this:
\[{(x^2+6x+14-14)} / (x^2+5x-6)\]

that is
\[(x^2+6x)/(x^2+5x-6)\]

Answer 10

now see: x^2+ 6x= x(x+6)
and x^2+5x-6 =(x-1)(x-6)
that is
\[(x^2+6x)/(x^2+5x-6)\] = \[{x(x+6)}/({x-1)(x+6)}\]

Answer 11

that is \[x/(x-1)\]

Answer 12

kensey sorry for slow replies my net was disconnecting
but finally i had answered :)
got it kensey any problem u can ask me now

Answer 13

THANK YOU SO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 14

a medal would be gr8