Question

help me with this question

Answer 1

Jai hanuman mangal murthi

Answer 2

haha ,bhaiya : jai hanuman
well my question is

Answer 3

\[\log_{7} \log_{5} (\sqrt{x+5} + \sqrt{x}) = 0\]

Answer 4

find the solution

Answer 5

7^0 = log5 ((x+5)1/2 + x^1/2)
\[5 = \sqrt{x+1}+\sqrt{x}\]
square both sides
25= x+1 + x+ 2 (x^2+x)^1/2
25 = 2x + 1 + 2(x^2+x) ^1/2
2(x^2+x)^1/2= 24- 2x
(x^2+x)^1/2 = 12- x
square again both sides
\[x^2+x = 144 +x^2 - 24 x\]
25x =144
x =144/25

Answer 6

no option like that

Answer 7

please give me options

Answer 8

x=4

Answer 9

\[\log _7\left(\log _5\left(\sqrt{x+5}+\sqrt{x}\right)\right)=0\]?

Answer 10

2,5,-5,4

Answer 11

ah, i see what happened vicky, you accidentally put:
\[\sqrt{x+1}\]instead of\[\sqrt{x+5}\]

Answer 12

\[\sqrt{x+5}+\sqrt{x}=5\]
x+5=x-10*sqrt(x)+25
\[\sqrt{x}=2\]
so x=4

Answer 13

i was looking at the steps and saying, "man, i dont see anything wrong with this!" lolol

Answer 14

5
-5
2
4

Answer 15

x can not be negative

Answer 16

help me any1