Question

5/x-1 + 3/x+1 = -4x/x^2 - 1

Answer 1

\[\frac{5}{x-1}+\frac{3}{x+1}= -\frac{-4x}{x^2-1}\]this?

Answer 2

yes

Answer 3

\[x = -\frac{1}{6}\]

Answer 4

LCM of (x-1)and (x+1) =(x-1)*(x+1)
now u can easily solve this
\[5/(x-1) + 3/(x+1)\] let us forget the right hand side
ok
now
\[[5(x+1)+3(x-1)]/(x-1)(x+1)\]
\[(5x+5+3x-3 )/(x^2-1)\]
\[(8x+2)/(x^2-1)\]
now it is the turn of right hand side
transpose it to left hand side
\[(8x+2)/(x^2-1)\] +\[4x/(x^2-1)\]
that is equal to
\[(8x+2+4x)/(x^2-1)\] =0
\[(12x+2)/(x^2-1)\] = 0
12x+2= 0
12x=-2
x=12/(-2)
x=-6

Answer 5

kush, u r wrong.

Answer 6

yes sorry i did wrong between

Answer 7

the answer is -1/2
(8x+2-4x)/(x^2-1)=0
4x+2=0
4x=-2
x=-1/2

Answer 8

no it says thats the wrong answer

Answer 9

Mine is right!
otherwise check the equation.

Answer 10

urs is right saif

Answer 11

I knew! :D

Answer 12

:D