Question

How to find Horizontal Asymptote of: (2x+1)/(x-2)

Answer 1

it's when the function = zero in the numerator...

so it's when 2x+1 = 0

for vertical asymptote it's when the function is undefined so when x-2 = 0

Answer 2

you have the correct way to find the vertical asymptote ryan, but not the horizontal

Answer 3

Yes, I know the Vertical, I was inquiring about the Horizontal.

Answer 4

since the degrees are equal, simply divide the leading coefficients to get 2/1 = 2

So the horizontal asymptote is y = 2

Answer 5

If the degree of the denominator is larger, then the horizontal asymptote is simply y = 0

Answer 6

If the degree of the numerator is larger, then you have to use polynomial long division (but at this point, you won't have a horizontal asymptote)

Answer 7

So, if equal degrees, you just divide it out.
If denominator degree is greater, the y asymptote is simply 0.
and if the numerator degree is greater, you use long division and have a slant asymptote.

Is that correct?

Answer 8

you are exactly correct !! Abe!!

Answer 9

that is correct, either a slant asymptote or something a bit more complicated

Answer 10

Thank you very much Jim and Star.