Question

please answer my question ,i need the help its very difficult,(4^3/5.2^4/5)^5/12

Answer 1

gosh!!,i love math,sometimes i hate math,,coz there's a time comes that math is very difficult

Answer 2

you meant
\[(4^{\frac{3}{5}}\times 2^{\frac{4}{5}})^{\frac{5}{12}}\] right?

Answer 3

so again gimmick is to write
\[4=2^2\] so
\[4^{\frac{3}{5}}=(2^2)^{\frac{3}{5}}=2^{\frac{6}{5}}\]

Answer 4

so you have
\[2^{\frac{6}{5}}\times 2^{\frac{4}{5}}=2^{\frac{10}{5}}=2^2=4\]

Answer 5

thank you!!!

Answer 6

yw but hold on let me check my work because it is early

Answer 7

ukie

Answer 8

yeah it is right but you are not done because you still have to raise to the power of 12/5 so you get
\[(2^2)^{\frac{5}{12}}=2^{\frac{5}{6}}=\sqrt[6]{2^5}\]

Answer 9

thank you,.can i ask 1 more problem??

Answer 10

ask away

Answer 11

\[(2x^3/5)^5\div
(5y^4/5\])^5

Answer 12

\[(\frac{2x^3}{5})^5\times (\frac{5}{5y^4})^5\] is a start

Answer 13

"multiply by the reciprocal"

Answer 14

which i should mutiply by reciprocal???the last fraction??

Answer 15

yes i flipped it right?

Answer 16

now you can combine as one term to the power 5 if you like (since they are both raised to the fifth power) and get
\[(\frac{10x^3}{25y^4})^5\]

Answer 17

then maybe cancel a 5 inside the parentheses ( i should have done this first) to get
\[(\frac{2x^3}{5y^4})^5\]

Answer 18

i would leave it like that but you could also write
\[\frac{2^5x^1{5}}{5^5y^{20}}\] if you like

Answer 19

ukie thank you!!!

Answer 20

yw