What is the acceleration?
v(t) = 128 -32t?
and after 3 seconds?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you can take the derivative of this function, since acceleration is the second derivative of the position function or the drivative of the veloctiy function
OpenStudy (anonymous):
how show solution ty...
OpenStudy (anonymous):
cantor set, lagrange, good morning!
OpenStudy (anonymous):
Fractally urs....
OpenStudy (anonymous):
@woobin do you have to do it using the definition? because otherwise you do it in your head
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
What's the 3 seconds about, distance?
OpenStudy (anonymous):
gm satellite
OpenStudy (anonymous):
i don't know how to do it because if i take the derivative the acceleration will become a = 32 am i correct?
OpenStudy (amistre64):
-32
OpenStudy (anonymous):
\[v(t)=128-32t\]
\[a(t)=v'(t)=-32\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
a(3)=-32
OpenStudy (anonymous):
on account of "gravity sucks"
OpenStudy (amistre64):
im sure there is a sec^2 under it all?
OpenStudy (anonymous):
@estudier nope it is about the acceleration after 3 seconds.
OpenStudy (anonymous):
Need some initial conditions..
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
the acceleration is constant; its slowing down
OpenStudy (anonymous):
@sattelite73 how bout if u plug in the 3 seconds in the acceleration what will be the asnwer?
OpenStudy (anonymous):
Plug 3 into -32?
OpenStudy (anonymous):
a(3)=-32
OpenStudy (amistre64):
round peg square hole filosophee eh lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
into the a(t) = -32
OpenStudy (anonymous):
Why would u want to plug 3 into -32?
OpenStudy (amistre64):
integrate it from 0 to 3?
OpenStudy (anonymous):
because that's the condition.
OpenStudy (anonymous):
the derivative of acceleration is jerk
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i'm finding the acceleration after 3 seconds..
OpenStudy (anonymous):
Oh u mean evaluate the constant function a(t) at t = 3?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
constant.
OpenStudy (anonymous):
constant what do u mean? what will be the answer?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
What do u think the -32 means?
OpenStudy (amistre64):
it helps if you have some idea as to what your own question is asking for ...
OpenStudy (anonymous):
how about i'll type the whole problem can u answer it?
OpenStudy (amistre64):
oh, so your keeping secrets are ya :) that would be a good move
OpenStudy (anonymous):
you mean thats the whole problem?
Still Need Help?
Join the QuestionCove community and study together with friends!