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Mathematics 21 Online
OpenStudy (anonymous):

What is the acceleration? v(t) = 128 -32t? and after 3 seconds?

OpenStudy (anonymous):

you can take the derivative of this function, since acceleration is the second derivative of the position function or the drivative of the veloctiy function

OpenStudy (anonymous):

how show solution ty...

OpenStudy (anonymous):

cantor set, lagrange, good morning!

OpenStudy (anonymous):

Fractally urs....

OpenStudy (anonymous):

@woobin do you have to do it using the definition? because otherwise you do it in your head

OpenStudy (anonymous):

What's the 3 seconds about, distance?

OpenStudy (anonymous):

gm satellite

OpenStudy (anonymous):

i don't know how to do it because if i take the derivative the acceleration will become a = 32 am i correct?

OpenStudy (amistre64):

-32

OpenStudy (anonymous):

\[v(t)=128-32t\] \[a(t)=v'(t)=-32\]

OpenStudy (anonymous):

a(3)=-32

OpenStudy (anonymous):

on account of "gravity sucks"

OpenStudy (amistre64):

im sure there is a sec^2 under it all?

OpenStudy (anonymous):

@estudier nope it is about the acceleration after 3 seconds.

OpenStudy (anonymous):

Need some initial conditions..

OpenStudy (amistre64):

the acceleration is constant; its slowing down

OpenStudy (anonymous):

@sattelite73 how bout if u plug in the 3 seconds in the acceleration what will be the asnwer?

OpenStudy (anonymous):

Plug 3 into -32?

OpenStudy (anonymous):

a(3)=-32

OpenStudy (amistre64):

round peg square hole filosophee eh lol

OpenStudy (anonymous):

into the a(t) = -32

OpenStudy (anonymous):

Why would u want to plug 3 into -32?

OpenStudy (amistre64):

integrate it from 0 to 3?

OpenStudy (anonymous):

because that's the condition.

OpenStudy (anonymous):

the derivative of acceleration is jerk

OpenStudy (anonymous):

i'm finding the acceleration after 3 seconds..

OpenStudy (anonymous):

Oh u mean evaluate the constant function a(t) at t = 3?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

constant.

OpenStudy (anonymous):

constant what do u mean? what will be the answer?

OpenStudy (anonymous):

What do u think the -32 means?

OpenStudy (amistre64):

it helps if you have some idea as to what your own question is asking for ...

OpenStudy (anonymous):

how about i'll type the whole problem can u answer it?

OpenStudy (amistre64):

oh, so your keeping secrets are ya :) that would be a good move

OpenStudy (anonymous):

you mean thats the whole problem?

OpenStudy (anonymous):

He moved onto projectiles now.

OpenStudy (anonymous):

That's the whole question..

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