What is the easiest way to find the intersection point of: (x)^3 = cube root of {x+3} ?
Btw, they are inverses of each other.
WAIT!
One minute, I messed up the beginning equation
its cube on left side and cuberoot on other side?
its actually suppose to be: (x^3 - 1) = cube root of (x + 1)
DISREGARD THE FIRST POST; It is suppose to be: (x^3 - 1) = cube root of (x + 1)
What is the easiest way of finding the intersection pt?
Cube both sides
Ok then..
it is not that easy.. Try trial and error method by plugging in different values for x
So it can't be solved out easily through algebra?
graph it
graph x^3 - 1 then graph cube root(x+3)
Then find the intersection point
Ok so I am suppose to guesstimate here?
Yes,,, you can estimate.. or use calculator to graph two equations.. one the left side and the other the right side// Answer would be 1.32472
You guys have contradicting answers, but its OK. I will just plot it on WolframAlpha and see what I get. Thanks in advance.
I graphed it and found the intersection point
http://www.wolframalpha.com/input/?i=%28x^3+-+1%29+%3D+cube+root+of+%28x+%2B+1%29
Shucks. Had warrior posted it correctly the first time....
That explains why we had conflicting answers
Intersection point is (1.32, 1.32)
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