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If g(x) = 3x - 5 find g-1(x)
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Help Please
To find the inverse, plug in g-1(x) into g(x) and solve for the x.
Err solve for the g^-1(x) rather
so can you show me?
\[g(g^{-1}(x)) =x \]\[\therefore\ g(g^{-1}(x)) = 3(g^{-1}(x)) - 5\]\[\implies x = 3(g^{-1}(x)) - 5\] Now solve for \(g^{-1}(x)\)
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so what is g
is it going to equal x + 5 /3
or one of these 3x + 5 5 - 3x -3x + 5
Did you solve for it?
Add 5 to both sides,the divide both sides by 3.
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so its going to be x+5/3
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