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Mathematics 17 Online
OpenStudy (anonymous):

Solve for x: 10^(6x+6)=5

OpenStudy (amistre64):

i dunno, x looks pretty comfy there, im afraid to disturb it and have it all grumpy

OpenStudy (anonymous):

To bring variable expressions out of the exponents use a log. (log base 10 is a nice one for this since the base of the power is 10 here and log base 10 can be done with a calculator)

OpenStudy (amistre64):

i was thinking to use the log10 meself, dont want to rock the boat and wake that sleeping giant tho

OpenStudy (anonymous):

How do I use log to bring the variable out of the exponent?

OpenStudy (amistre64):

\[B^x=N\] \[log_B(B^x)=log_B(N)\] \[x=log_B(N)\] is the results

OpenStudy (amistre64):

or how to get to the results; logs undo exponents; and exponents undo logs; they are inverses

OpenStudy (amistre64):

\[10^{(6x+6)}=5\] \[log_{10}10^{(6x+6)}=log_{10}5\] \[6x+6=log_{10}5\] \[6x=log_{10}(5)-6\] \[x=\frac{log_{10}(5)}{6}-\frac{6}{6}\]

OpenStudy (anonymous):

Ok, makes sense to me. Thanks.

OpenStudy (amistre64):

the log <-> exp relation is just like the * <->/ and the + <-> - relations; they undo each other when the time comes

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