I need help with finding the intercepts of these equations y=X^2(sqrt( 25-X^2) and y=3(2- sqrt (x))/over x
you want where the equations intersect? or do you really want the intercepts of each?
i want like x intercepts and y and how you re-arrange the equation
to find x-intercept(s), set y=0 and solve for x. to find y-intercept(s), set x=0 and solve for y
so for example: we have \[y=x^2\sqrt{25-x^2}\]. to find x-intercepts set y=0 and solve for x. \[0=x^2\sqrt{25-x^2}\]
\[x^2=0, \sqrt{25-x^2}=0\]
\[x=0, x=\pm 5\]
you have 3 x-intercetps (0,0) (5,0) (-5,0)
oooh can you pls do the next one the square roots and division sign confuse m when settin them = to 0
now to find the y-intercept set x=0 and solve for y \[y=0^2\sqrt{25-0^2}=0\sqrt{25}=0\] so we have y-intercept is (0,0) but could have prevented doing this step since we already found the y-intercept above
for the other equation?
oops one second
to find y-intercepts set x=0but what happens when you plug 0 in where x is?
you mean y = 0 to find x intercepts?
the square root disapear?
don't you have x in the denominator?
oh ya
so the function is undefined when x=0 so no y-intercepts
now to find x-intercepts, set y=0 and solve for x
i c, can you showme steps when setting 6-3(squrt x)=0
like how you move the 3 and so on
a fraction is only zero when the stop is zero so we are looking at solving \[0=3(2-\sqrt{x})\]
divide both sides by 3
then add square root of x on both sides
and then square both sides
oooh thanks can you show sqrt part so i can c visuallysrory
then show x= and x= so i can check
show me what you think i just asked you to do and i will be right back i have to get to ready to go to sleep
ok so 3=0 and (2-squrtX=0?
ok so 3=0 and (2-squrtX=0?
well 3 is not equal to 0 so we have \[2-\sqrt{x}=0\] add \[\sqrt{x}\] on both sides
then square both sides
oh could u also have subtracted 2?
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