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Mathematics 16 Online
OpenStudy (anonymous):

natural number cannot be a fraction, decimal, or square root?

OpenStudy (anonymous):

ture

OpenStudy (zarkon):

\[\sqrt{25}\] ;)

OpenStudy (anonymous):

resulting in -5 as well zarkon meaning its not natural

OpenStudy (anonymous):

lol @ outcast

OpenStudy (zarkon):

um..no

OpenStudy (zarkon):

\[\sqrt{25}=5\]

OpenStudy (anonymous):

+/- 5

OpenStudy (zarkon):

no it is not...the notation \[\sqrt{}\] uses only the principal value

OpenStudy (anonymous):

what?

OpenStudy (zarkon):

look it up if you don't know it

OpenStudy (anonymous):

sorry then sir i bow to ur wisdom

OpenStudy (anonymous):

can u link me?

OpenStudy (anonymous):

even at that, what you are saying is that all sqrt are natural numbers

OpenStudy (anonymous):

sqrt of 235928395819481342 is not going to be a natural number when you take the root

OpenStudy (anonymous):

but there's a negative value possible too i dont get principle stuff

OpenStudy (zarkon):

it is a notation thing....if you just ask for the square root of a number then it is true that is it +- if you ask for \[\sqrt{a}\] then the answer is just the principal value (the positive real number...provided a>0) so for this problem square roots are bad (that is why I put the smiley face)

OpenStudy (anonymous):

SO, basically, You can hv a square root of something and it could also be negative AND positive, right? so the square root of somethuing is (therefore) NOT natural???

OpenStudy (anonymous):

i thought only imaginary numbers were given the principle value

OpenStudy (zarkon):

that is true if you use words to ask for the square root

OpenStudy (anonymous):

DUDE. I M SOOOOOOO LOST!!!

OpenStudy (zarkon):

square root of 25 is \[\pm5\] \[\sqrt{25}=5\] \[(25)^{1/2}=5\]

OpenStudy (anonymous):

i still dont get it

OpenStudy (zarkon):

http://en.wikipedia.org/wiki/Square_root

OpenStudy (anonymous):

There are two square roots of 25. One is 5, one is -5. The notations \(\sqrt{a}\) refers to the positive square root if you want the negative one you would write \(-\sqrt{a}\). If you wanted both you'd write \(\pm \sqrt{a}\)

OpenStudy (anonymous):

Every non-negative real number x has a unique non-negative square root

OpenStudy (anonymous):

even by definition it does not include natural numbers

OpenStudy (anonymous):

Uh.. Natural numbers are a subset of the Reals.

OpenStudy (zarkon):

\[\frac{5}{1}\]...fraction ;)

OpenStudy (anonymous):

yes i get what u mean but its not true for all

OpenStudy (anonymous):

I meant...1/5

OpenStudy (anonymous):

then no

OpenStudy (anonymous):

i get what u mean zarkon

OpenStudy (zarkon):

it says cannot be a fraction...well it can \[\frac{n}{1}\] ;)

OpenStudy (anonymous):

I dont

OpenStudy (anonymous):

lol sorry it took me this long to understand

OpenStudy (anonymous):

well its the same as saying 1 can be written as 1.0

OpenStudy (anonymous):

or 1/1

OpenStudy (anonymous):

The statement says a natural number cannot be a fraction or a square root or a decimal. But we've given examples of natural numbers that are. Therefore the statement is false.

OpenStudy (anonymous):

if u are in a lower grade i think it would be safe to just say yes

OpenStudy (anonymous):

I dont' exactly know for sure, but... to sum it up... I would say that \[\sqrt{x}\] would be the one that comes out positive, and \[-\sqrt{x}\] right???

OpenStudy (zarkon):

what class/level is this?

OpenStudy (anonymous):

and ther are loopholes to every statement? Oh, and Its Pre AP algebra 2 that Im taking in eighth grade(ya,I'm so cool) lol

OpenStudy (anonymous):

zarkon i need help on a question as wwell are u busy?

OpenStudy (anonymous):

hahd, you r so awesome!!! Thank you !!! I m goin to become fan!!!

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