natural number cannot be a fraction, decimal, or square root?
ture
\[\sqrt{25}\] ;)
resulting in -5 as well zarkon meaning its not natural
lol @ outcast
um..no
\[\sqrt{25}=5\]
+/- 5
no it is not...the notation \[\sqrt{}\] uses only the principal value
what?
look it up if you don't know it
sorry then sir i bow to ur wisdom
can u link me?
even at that, what you are saying is that all sqrt are natural numbers
sqrt of 235928395819481342 is not going to be a natural number when you take the root
but there's a negative value possible too i dont get principle stuff
it is a notation thing....if you just ask for the square root of a number then it is true that is it +- if you ask for \[\sqrt{a}\] then the answer is just the principal value (the positive real number...provided a>0) so for this problem square roots are bad (that is why I put the smiley face)
SO, basically, You can hv a square root of something and it could also be negative AND positive, right? so the square root of somethuing is (therefore) NOT natural???
i thought only imaginary numbers were given the principle value
that is true if you use words to ask for the square root
DUDE. I M SOOOOOOO LOST!!!
square root of 25 is \[\pm5\] \[\sqrt{25}=5\] \[(25)^{1/2}=5\]
i still dont get it
There are two square roots of 25. One is 5, one is -5. The notations \(\sqrt{a}\) refers to the positive square root if you want the negative one you would write \(-\sqrt{a}\). If you wanted both you'd write \(\pm \sqrt{a}\)
Every non-negative real number x has a unique non-negative square root
even by definition it does not include natural numbers
Uh.. Natural numbers are a subset of the Reals.
\[\frac{5}{1}\]...fraction ;)
yes i get what u mean but its not true for all
I meant...1/5
then no
i get what u mean zarkon
it says cannot be a fraction...well it can \[\frac{n}{1}\] ;)
I dont
lol sorry it took me this long to understand
well its the same as saying 1 can be written as 1.0
or 1/1
The statement says a natural number cannot be a fraction or a square root or a decimal. But we've given examples of natural numbers that are. Therefore the statement is false.
if u are in a lower grade i think it would be safe to just say yes
I dont' exactly know for sure, but... to sum it up... I would say that \[\sqrt{x}\] would be the one that comes out positive, and \[-\sqrt{x}\] right???
what class/level is this?
and ther are loopholes to every statement? Oh, and Its Pre AP algebra 2 that Im taking in eighth grade(ya,I'm so cool) lol
zarkon i need help on a question as wwell are u busy?
hahd, you r so awesome!!! Thank you !!! I m goin to become fan!!!
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