Question

Can someone help me to solve the following inequality?

Answer 1

Can you show the work, please?

Answer 2

clear the fraction by multiplying both sides by the denom

Answer 3

yeah

Answer 4

then migrate it all to one side of the sign

Answer 5

and solve as a quadratic

Answer 6

or, another way to look at it; is (x+1)/(x+1) = 1, so use that and ignore the denoms

Answer 7

is this correct?

x^2 + 3x >= 0

Answer 8

x^2 +4x + 1 >/ x+1

x^2 +3x >/ 0, looks good to me; factor and dbl chk

Answer 9

then I should solve it as a normal inequality?

Answer 10

there should be someway to teach or get across to the masses that =,>, and < have all the same properties and are the same type of problems

Answer 11

there is nothing magical about any of the symbols of equaltiy relations

Answer 12

Im gonna edit the way I think, it is the correct. Then you can find the mistakes

Answer 13

ok :)

Answer 14

thanks ;)

Answer 15

this is the first part

Answer 16

good so far :)

Answer 17

ok

Answer 18

those numbers are good for reference, but lets use them in a reasonable fashion now :)

Answer 19

can you follow this link: http://www.twiddla.com/602089 Im making a draw

Answer 20

so our solutions is: (-inf,-3] U [0,inf)

Answer 21

Very Informative, thanks emunrradtvamg and amistre64

Answer 22

youre welcome :)

Answer 23

Sorry my internet connection failed. So according to what we know the answer is the above mencioned, but according to my book the answer is:

Answer 24

-3 <= x < -1 and x>=0

Answer 25

there is where my question starts

Answer 26

and this is where my yesterday question started

Answer 27

we have to address this as it relates to the original problem

Answer 28

we did the factors which gave us the criticals and forgot to address the orignial statement

Answer 29

\[\frac{x^2+4x+1}{x+1}\]this is what we need to address :)

Answer 30

can you show the work please. Coz im getting utterly confused again

Answer 31

do you see this
\[\frac{x^2+4x+1}{x+1}\ \ne\ x^2+3x\]

Answer 32

I just did that

Answer 33

We have to pass the 1 to the left hand side first and then get the common denominator, right

Answer 34

have to? no, it all works out the same

Answer 35

so this is what we end up with