Hello! Can someone please teach me how to answer this problem?
Determine the equation of line tangent to the graph of y^3=3x+2 at x=-1.
The y^3 puzzles me a lot. :(

Question

nilankshi · Answer

help me also @ vicky007

anonymous · Answer

take derivatives on both side you will finally get dy/dx = 1/y^2
now this is the slope of the tangent 
from x = -1 find the value of y by plugging x in 3y^= 3x+2
then find equation of tnagent in point slope form

anonymous · Answer

Okay, I'll absorb this first. And thank you! I'll post a follow up if I don't understand something. :)

anonymous · Answer

Hey again! Is the answer y=x-2?