Question

question on this integral, should i divide and what would it look like if i did

Answer 1

\[\int\limits_{}^{}(3x^2+2x)/(x+1)\]

Answer 2

3(-1)^2 +2(-1) ?=? 0

Answer 3

factor the top; and split it up maybe?

Answer 4

\[\frac{3x^2+2x}{x+1}=\frac{x(3x+2)}{x+1}=\frac{x}{x+1}....\]
maybe not :)

Answer 5

i did long dividion but i got left with a remainder or -x

Answer 6

i am unsure of how i can proceed from there

Answer 7

remainder should be 1 i thin

Answer 8

well, -1 right, casue -x =-1

Answer 9

integrate by parts; numerator as u and denominator as v?

Answer 10

well, i guess i can do that, but i think i was suppose to incorporate susbtitution somehwere

Answer 11

is there a different way to right the results after you divide poynomial?

Answer 12

there is always a different way :) some gooder and some not so gooder

Answer 13

http://www.wolframalpha.com/input/?i=%E2%88%AB%283x2%2B2x%29%2F%28x%2B1%29

Answer 14

cause i looked in a precalc book and it ws dividing (6x^2-26x+12)/ (x-4), and it wrote the results as : (6x-2)+((x)/(x-4)

Answer 15

and if i could write it that way, then my life would be good

Answer 16

cause i can just break it up

Answer 17

thanks vicky for the link, but i cant look at that site, it will root my brain

Answer 18

3x -1 + \(\cfrac{1}{x+1}\)
------------
x+1 | 3x^2 + 2x
-3x^2 -3x
----------
-x
+x+1
-------
1

Answer 19

lol .... that dint format like i wanted

Answer 20

\[\int (3x -1 +\frac{1}{x+1})dx\]

Answer 21

but that -1 should really be -x thought right

Answer 22

no

Answer 23

it would have looked better had the site parsed by carriage returns; but