Question

someone help me pleez! what is ILATE?

Answer 1

sounds like an applet designed to make you miss all your appointments

Answer 2

this is a cool acronym

Answer 3

lol

Answer 4

althoug i think it may be spelled wrong. The way i spell it it , LIATE

Answer 5

It basically is : Lilliputians In Africa Tackle Elephants

Answer 6

I->Inverse
L->Log
A-> Algebraic
T-> Trig
E-> Exponential

Answer 7

It's short for I'm Late

Answer 8

Logs-->Inverse Trig-->Algebra---->Trig--->Exponetial

Answer 9

Yup ^_^ looks better

Answer 10

No, he asked ILATE..... Inverse-->Log-->Algebraic ---> Trig--->Exponential

Answer 11

oh, i assumed the other one, I am so use to it :)

Answer 12

Let v and u be function of x
\[\int u.v dx = v\int u dx - \int(\int u dx \frac{d (v)}{dx})\]
Order of choosing v.

Answer 13

i have never heard of it before and, as we say in the math biz, "i don't get it"

Answer 14

its used for picking the u in integration by parts

Answer 15

It's not important just a way for students to memorize things not important

Answer 16

In india any student prepering for IIT JEE must be aware of all such tricks tips and logic bits

Answer 17

ok like PEMDAS that knows somebody

Answer 18

Bah, pick something u can integrate...

Answer 19

no not necessary @vicky

Answer 20

so if you want to integrate by parts first you look at "inverse"?

Answer 21

is that supposed to be your u or your dv?

Answer 22

since an inverse trig function derives to a baser form; its a good pick

Answer 23

Suppose to be the U

Answer 24

everything else should be dv

Answer 25

\[\int\tan^{-1}(x)\ln(x)x^2dx\]

Answer 26

nu inverse is v if any other its u

Answer 27

there is my example. so first take out the
\[\tan^{-1}(x)\]?

Answer 28

lol ... multiple perversions

Answer 29

lol

Answer 30

lol

Answer 31

you have a tri product; which you would have to develop a newer method for

Answer 32

just trying to follow along. because it is new to me

Answer 33

int by parts comes from the product rule

Answer 34

oh i thought it was like "first this, then that, then the other"

Answer 35

\[[uv]'=uv' + vu'\]
i just love how the font makes all the letters look exactly alike

Answer 36

ok fine lets make it simpler then.
\[\int \tan^{-1}(x)\ln(x)dx\] what does iLATE tell me?

Answer 37

tan^-1x is the first term in the rule...

Answer 38

ok

Answer 39

"inverse" got it. and then?

Answer 40

\[[uv]'=uv' + vu'\]
\[\int[uv]'=\int uv' +\int vu'\]
\[uv=\int uv' +\int vu'\]
\[uv- \int vdu=\int udv \]

Answer 41

ln would be dv

Answer 42

...

Answer 43

logarithmic then.. its the 2nd function in ILATE

Answer 44

I like the iLate app idea more.

Answer 45

so diff. the inverse trig, and integrate the ln

Answer 46

I Like A Tobe Expert...

Answer 47

i sent it to steve jobs. he looked at my idea and quit!

Answer 48

Tobe?

Answer 49

ILATE isnt PEDMAS, its just a memory device to keep you aware of what you could pick

Answer 50

LOL

Answer 51

lol@satellite

Answer 52

ILATE is like pedmas right?>

Answer 53

pedmas says do it in this order; ilate says these are good picks

Answer 54

ok now i am actually really confused.

Answer 55

one is permutations and the other is combonations :)

Answer 56

order counts in pedmas; not in ilate

Answer 57

i put
\[\int\tan^{-1}(x)\ln(x)dx\] and apparently arctangent comes before log in ilate. so what does that tell me?

Answer 58

but ILATE rule is not applicable to every integration sometime it leads to very complicated equation to integrate I personally feel it's not good I may be wrong but I don't like the ILATE rule

Answer 59

i don't know if i like it or not because i don't understand it still.

Answer 60

since integration is more art than science; there is no concrete rule for what has to be picked out when and where

Answer 61

so its more of a suggestions as to what can be used for "u"

Answer 62

ilate tells you
\[tan^{-1}x \int logx dx - \int[ \int logxdx \times \frac{d}{dx} \times tan^{-1}x]\]

Answer 63

We had a debate in our college whether ILATE or LIATE is right..
Final conclusions were
!. It won't come in your examinations
2.Use either if you have both together you will have to use it twice like if u integrate lnx u will have to find the integral by the same rule in a separate step

Answer 64

Yes completely agree with Amistre

Answer 65

I prefer LIATE

Answer 66

i just use the acronym: wolframalpha.com :)

Answer 67

god now i know how people who post
"hlep me pllleeeeeez x^2-4"
feel because i still don't get it. i know how to integrate by parts, (although i alway forget whether you are supposed to say u dv or v du) but i can't make heads of tails of this

Answer 68

what is that you not getting??

Answer 69

you could just as well say m ds and s dm

Answer 70

lol amistre

Answer 71

oh here always take the function with more preference according to ILATE as v

Answer 72

♫ d☺ and ☺ d♫

Answer 73

lol

Answer 74

lol

Answer 75

what it tells me to do. apparently i picked a bad example because i had IL and it might be IL or LI, so let me pick a different one
\[\int x^3\tan^{-1}(x)dx\] something not ambiguous. what does ILATE say?

Answer 76

tan-1 should be derived since it "reduces" to a baser form that can be worked with easier than it suits up

Answer 77

that you differentiate tan^-1x and integrate x^3

Answer 78

oh bless you! as we say in math class "i get it"

Answer 79

ilate gives order in which you differentiate!

Answer 80

yes

Answer 81

yup

Answer 82

thank you all.

Answer 83

suggests candidtaes for deriving

Answer 84

lol

Answer 85

i like the way amistre answers!!!

Answer 86

me too

Answer 87

i type for the dyslexic imparied :)

Answer 88

now how do you find the vertex of
\[y=x^2-2x+3\]?

Answer 89

first we have to define a vertex so that it makes sense :)

Answer 90

ask wolfram

Answer 91

2/2 = 1\

Answer 92

parabola y+1 = (x-2)^2
vertex 2,1

Answer 93

None is answering any questions, lol

Answer 94

can anybody see the starting of this question!!!!!!!!!!!!1

Answer 95

well, all the same group is asking questions that theyve already been given the answers to over and over again :)

Answer 96

lol amistre

Answer 97

\[\color{Indigo}{\Huge{\text{iLate}}}\]

Answer 98

i---->late