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Mathematics 21 Online
OpenStudy (anonymous):

Help me? I don't understand this stuff.... files attached.

OpenStudy (anonymous):

Document form.

OpenStudy (anonymous):

PDF form.

OpenStudy (anonymous):

Please help with any of the questions that you can... I'm LOST.

OpenStudy (anonymous):

we love pdf form!

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

ok your job here is to multiply. in each case you will have to do FOUR multiplications, just like you would if you multiplied two 2-digit numbers

OpenStudy (anonymous):

lets start with \[(x-5)^2\] which means \[(x-5)(x-5)\]

OpenStudy (anonymous):

please don't put \[(x-5)^2=x^2-25\]or your math teacher will think you are a moron. you have to first write out \[(x-5)(x-5)\] and then perform FOUR multiplications

OpenStudy (anonymous):

like this \[(x-5)(x-5)=x\times x - x \times 5 - 5 \times x - 5 \times -5\] \[x^2-5x-5x+25\] \[x^2-10x+25\]

OpenStudy (anonymous):

with a little practice you will see that \[(x-b)^2=x^2-2bx+b^2\] but at the beginning just multiply out

OpenStudy (anonymous):

ok... so I just do the distributive property when multiplying?

OpenStudy (anonymous):

first problem \[(a-b)(a-b)=a\times a -a \times b-b\times a -b \times -b\] \[a^2-2ab+b^2\]

OpenStudy (anonymous):

yes the distributive property. you have it exactly!

OpenStudy (anonymous):

make sure to do all FOUR multiplications if it is two terms times two terms. the answer to question one is SOMETIMES

OpenStudy (anonymous):

it would be true for example if \[b=0\]

OpenStudy (anonymous):

if you want, try #3 and i will check your answer

OpenStudy (anonymous):

Okay... I will.

OpenStudy (anonymous):

Okay, (x+3)^2 (x+3)(x+3) x^2+x3+x3+9 x^2+6x+9 so option one. ???

OpenStudy (anonymous):

ohh, forgot about formatting problems...

OpenStudy (anonymous):

yes you have it exactly

OpenStudy (anonymous):

feel free to post the next two as well

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