Mathematics
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OpenStudy (anonymous):
Solve the following inequality and give your answer in interval form. x^3-x^2 > 2x
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OpenStudy (akshay_budhkar):
whats your simplified form? you did that right?
OpenStudy (anonymous):
x(x-2)(x-1)>0
OpenStudy (akshay_budhkar):
see this... I will explain you still if you do not get it
OpenStudy (akshay_budhkar):
You get it?
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OpenStudy (akshay_budhkar):
oh satellite is here.. You can be tension free now..
OpenStudy (anonymous):
you can see in your mind that
\[x(x-2)(x-1)\] is a polynomial of degree 3 and so it looks like |dw:1314289686271:dw|
OpenStudy (anonymous):
so the solutions are (-1,2)
OpenStudy (anonymous):
the original equation was x^3-x^2> 2x
OpenStudy (anonymous):
d
\[x^3-x^2-2x>0\]
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[x(x^2-x-2)>0\]
\[x(x+1)(x-2)>0\]
OpenStudy (anonymous):
first question, where is it zero?
answer at -1, 0, and 2
OpenStudy (anonymous):
yes so how do i express that in interval form
OpenStudy (anonymous):
so (-1,2)
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OpenStudy (anonymous):
we are not done yet, we only know where it is 0
OpenStudy (anonymous):
sloooowly now
OpenStudy (anonymous):
now we want to know where it is greater than zero right?
OpenStudy (anonymous):
so do a critical number line?
OpenStudy (anonymous):
if you like to spend extra time yes, or if your teacher makes you.
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OpenStudy (anonymous):
but we can draw a picture of some general cubic polynomial with positive leading coefficient. it looks like |dw:1314289994031:dw|