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Mathematics 14 Online
OpenStudy (anonymous):

Solve the following inequality and give your answer in interval form. x^3-x^2 > 2x

OpenStudy (akshay_budhkar):

whats your simplified form? you did that right?

OpenStudy (anonymous):

x(x-2)(x-1)>0

OpenStudy (akshay_budhkar):

see this... I will explain you still if you do not get it

OpenStudy (akshay_budhkar):

You get it?

OpenStudy (akshay_budhkar):

oh satellite is here.. You can be tension free now..

OpenStudy (anonymous):

you can see in your mind that \[x(x-2)(x-1)\] is a polynomial of degree 3 and so it looks like |dw:1314289686271:dw|

OpenStudy (anonymous):

so the solutions are (-1,2)

OpenStudy (anonymous):

the original equation was x^3-x^2> 2x

OpenStudy (anonymous):

d \[x^3-x^2-2x>0\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[x(x^2-x-2)>0\] \[x(x+1)(x-2)>0\]

OpenStudy (anonymous):

first question, where is it zero? answer at -1, 0, and 2

OpenStudy (anonymous):

yes so how do i express that in interval form

OpenStudy (anonymous):

so (-1,2)

OpenStudy (anonymous):

we are not done yet, we only know where it is 0

OpenStudy (anonymous):

sloooowly now

OpenStudy (anonymous):

now we want to know where it is greater than zero right?

OpenStudy (anonymous):

so do a critical number line?

OpenStudy (anonymous):

if you like to spend extra time yes, or if your teacher makes you.

OpenStudy (anonymous):

but we can draw a picture of some general cubic polynomial with positive leading coefficient. it looks like |dw:1314289994031:dw|

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