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OpenStudy (anonymous):
Divide and check.
9x^2 + 3x – 2 / 3x

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OpenStudy (saifoo.khan):
\[\frac{9x^2 + 3x – 2}{3x}\]
is it like this?

OpenStudy (anonymous):
yes

OpenStudy (mimi_x3):
lols , is it possible to divide ?
i got
(3x-1)(3x+2)/3x

OpenStudy (mimi_x3):
Saifoo can help xD

OpenStudy (saifoo.khan):
Sure. help him.

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OpenStudy (saifoo.khan):
i think jb copied an incomplete problem.

OpenStudy (mimi_x3):
lols , incomplete xD

OpenStudy (anonymous):
I coppied the correct problem

OpenStudy (saifoo.khan):
there is something missing in the end.

OpenStudy (mimi_x3):
but it cant be simplified further . So how can it be divide

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OpenStudy (mimi_x3):
yeah true something is missing xD

OpenStudy (anonymous):
double checking now

OpenStudy (anonymous):
that's the correct problem. nothing else on the end

OpenStudy (mimi_x3):
are yu sure ? i think that is missing either (3x-1) or (3x+2) at the end

OpenStudy (mimi_x3):
it is*

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OpenStudy (anonymous):
positive

OpenStudy (mimi_x3):
positive ?

OpenStudy (anonymous):
nothing else on the problem. that's it all there is. there are some others similar to this one

OpenStudy (mimi_x3):
LOL, it cant be divided then xD

OpenStudy (anonymous):
ok

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jimthompson5910 (jim_thompson5910):
\[\large \frac{9x^2 + 3x – 2}{3x}\]
\[\large \frac{9x^2}{3x} + \frac{3x}{3x} – \frac{2}{3x}\]
\[\large 3x + 1 – \frac{2}{3x}\]
So \[\large \frac{9x^2 + 3x – 2}{3x}=3x + 1 – \frac{2}{3x}\]
Note: the quotient here is 3x+1 and the remainder is -2

OpenStudy (anonymous):
The answer is:
3x+1 with a remainder of -2

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