Mathematics
38 Online
OpenStudy (anonymous):
Divide and check.
9x^2 + 3x – 2 / 3x
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OpenStudy (saifoo.khan):
\[\frac{9x^2 + 3x – 2}{3x}\]
is it like this?
OpenStudy (anonymous):
yes
OpenStudy (mimi_x3):
lols , is it possible to divide ?
i got
(3x-1)(3x+2)/3x
OpenStudy (mimi_x3):
Saifoo can help xD
OpenStudy (saifoo.khan):
Sure. help him.
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OpenStudy (saifoo.khan):
i think jb copied an incomplete problem.
OpenStudy (mimi_x3):
lols , incomplete xD
OpenStudy (anonymous):
I coppied the correct problem
OpenStudy (saifoo.khan):
there is something missing in the end.
OpenStudy (mimi_x3):
but it cant be simplified further . So how can it be divide
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OpenStudy (mimi_x3):
yeah true something is missing xD
OpenStudy (anonymous):
double checking now
OpenStudy (anonymous):
that's the correct problem. nothing else on the end
OpenStudy (mimi_x3):
are yu sure ? i think that is missing either (3x-1) or (3x+2) at the end
OpenStudy (mimi_x3):
it is*
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OpenStudy (anonymous):
positive
OpenStudy (mimi_x3):
positive ?
OpenStudy (anonymous):
nothing else on the problem. that's it all there is. there are some others similar to this one
OpenStudy (mimi_x3):
LOL, it cant be divided then xD
OpenStudy (anonymous):
ok
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jimthompson5910 (jim_thompson5910):
\[\large \frac{9x^2 + 3x – 2}{3x}\]
\[\large \frac{9x^2}{3x} + \frac{3x}{3x} – \frac{2}{3x}\]
\[\large 3x + 1 – \frac{2}{3x}\]
So \[\large \frac{9x^2 + 3x – 2}{3x}=3x + 1 – \frac{2}{3x}\]
Note: the quotient here is 3x+1 and the remainder is -2
OpenStudy (anonymous):
The answer is:
3x+1 with a remainder of -2