Question

Divide and check.

9x^2 + 3x – 2 / 3x

Answer 1

\[\frac{9x^2 + 3x – 2}{3x}\]

is it like this?

Answer 2

yes

Answer 3

lols , is it possible to divide ?
i got
(3x-1)(3x+2)/3x

Answer 4

Saifoo can help xD

Answer 5

Sure. help him.

Answer 6

i think jb copied an incomplete problem.

Answer 7

lols , incomplete xD

Answer 8

I coppied the correct problem

Answer 9

there is something missing in the end.

Answer 10

but it cant be simplified further . So how can it be divide

Answer 11

yeah true something is missing xD

Answer 12

double checking now

Answer 13

that's the correct problem. nothing else on the end

Answer 14

are yu sure ? i think that is missing either (3x-1) or (3x+2) at the end

Answer 15

it is*

Answer 16

positive

Answer 17

positive ?

Answer 18

nothing else on the problem. that's it all there is. there are some others similar to this one

Answer 19

LOL, it cant be divided then xD

Answer 20

ok

Answer 21

\[\large \frac{9x^2 + 3x – 2}{3x}\]


\[\large \frac{9x^2}{3x} + \frac{3x}{3x} – \frac{2}{3x}\]


\[\large 3x + 1 – \frac{2}{3x}\]
So \[\large \frac{9x^2 + 3x – 2}{3x}=3x + 1 – \frac{2}{3x}\]

Note: the quotient here is 3x+1 and the remainder is -2

Answer 22

The answer is:

3x+1 with a remainder of -2