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OpenStudy (anonymous):

solve 0.6x+8<0x-5

OpenStudy (anonymous):

\[0.6 x < -5 -8 \] \[0.6 x < \frac{-13}{0.6} \] \[x < - 21.666666666666666666666666666667\]

OpenStudy (anonymous):

Are you sure the coefficient for x in the right hand side is 0?

OpenStudy (anonymous):

no I am not I know it is less then or equal to

OpenStudy (anonymous):

I never did algebra and this is frustrating

OpenStudy (anonymous):

Don't worry, its all about practice. You can just treat inequality signs just like an equality sign. Just remember that when you divide by a negative number, you must invert the equality sign, i.e: \[ -3x \leq 2 \] \[ \frac{-3x \leq 2}{-3} \rightarrow x \geq \frac{-2}{3} \]

OpenStudy (anonymous):

thanks did it make a difference about the 6.0 vs0.6?

OpenStudy (anonymous):

Im sorry, i don't follow. Could you rephrase the question?

OpenStudy (anonymous):

oh you ask if the the 6 was on the right side of the problem it was written 0.6

OpenStudy (anonymous):

got time for another one?

OpenStudy (anonymous):

i asked abot the right hand side, not the left side. On the left you have 0.6 x +8 and on the right you have 0x -5. And that 0 confuses me, why did you even write it? And yes, show me the other one

OpenStudy (anonymous):

soybean meal is 12% protein Cornmeal 6% protein. How many lbs of each should be mixed together in order to get 240 lbs mix that is 10% proteing Corn mealLBS? Soybean lbs?

OpenStudy (anonymous):

Ok, I'm going to take a little time in order to write a full explanation.

OpenStudy (anonymous):

Fitst write equations to reflect what you know, let x be the amount of soybean in pounds and y be the amount of cornmeal in pounds. Then the total amount of mixture is (let's call this equation 1): \[x + y = 240\] And the total protein percentage is (let's call this equation 2): \[12x + 6y = 10(x+y)\] Substitute equation 1 in equation 2 and divide the whole thing by 6 to make things easier \[ \frac{12x + 6y = 10(240)} {6}\] \[ \frac{12x}{6} + \frac{6y}{6} = \frac{2400} {6}\] \[ 2x + y = 400\] Solve this for y: \[ y = 400 - 2x\] Now substitute this in equation 1: \[ (400 - 2x) + x = 240\] \[ 400 - x = 240\] \[ x = 400 - 240\] \[ x = 160\] Substitute the value back in equation 1: \[(160) + y = 240 \] \[ y = 240 -160 \] \[ y = 80 \] If you plug these values in equation 2 the equality must hold to check our results: \[12(160) + 6(80) = 10(160 + 80)\] \[2400 = 2400 \]

OpenStudy (anonymous):

If you have any questions please do ask, and if you like the answers push te good answer button :)

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