solve 0.6x+8<0x-5

\[0.6 x < -5 -8 \] \[0.6 x < \frac{-13}{0.6} \] \[x < - 21.666666666666666666666666666667\]

Are you sure the coefficient for x in the right hand side is 0?

no I am not I know it is less then or equal to

I never did algebra and this is frustrating

Don't worry, its all about practice. You can just treat inequality signs just like an equality sign. Just remember that when you divide by a negative number, you must invert the equality sign, i.e: \[ -3x \leq 2 \] \[ \frac{-3x \leq 2}{-3} \rightarrow x \geq \frac{-2}{3} \]

thanks did it make a difference about the 6.0 vs0.6?

Im sorry, i don't follow. Could you rephrase the question?

oh you ask if the the 6 was on the right side of the problem it was written 0.6

got time for another one?

i asked abot the right hand side, not the left side. On the left you have 0.6 x +8 and on the right you have 0x -5. And that 0 confuses me, why did you even write it? And yes, show me the other one

soybean meal is 12% protein Cornmeal 6% protein. How many lbs of each should be mixed together in order to get 240 lbs mix that is 10% proteing Corn mealLBS? Soybean lbs?

Ok, I'm going to take a little time in order to write a full explanation.

Fitst write equations to reflect what you know, let x be the amount of soybean in pounds and y be the amount of cornmeal in pounds. Then the total amount of mixture is (let's call this equation 1): \[x + y = 240\] And the total protein percentage is (let's call this equation 2): \[12x + 6y = 10(x+y)\] Substitute equation 1 in equation 2 and divide the whole thing by 6 to make things easier \[ \frac{12x + 6y = 10(240)} {6}\] \[ \frac{12x}{6} + \frac{6y}{6} = \frac{2400} {6}\] \[ 2x + y = 400\] Solve this for y: \[ y = 400 - 2x\] Now substitute this in equation 1: \[ (400 - 2x) + x = 240\] \[ 400 - x = 240\] \[ x = 400 - 240\] \[ x = 160\] Substitute the value back in equation 1: \[(160) + y = 240 \] \[ y = 240 -160 \] \[ y = 80 \] If you plug these values in equation 2 the equality must hold to check our results: \[12(160) + 6(80) = 10(160 + 80)\] \[2400 = 2400 \]

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