Question

solve 0.6x+8<0x-5

Answer 1

\[0.6 x < -5 -8 \]
\[0.6 x < \frac{-13}{0.6} \]
\[x < - 21.666666666666666666666666666667\]

Answer 2

Are you sure the coefficient for x in the right hand side is 0?

Answer 3

no I am not I know it is less then or equal to

Answer 4

I never did algebra and this is frustrating

Answer 5

Don't worry, its all about practice. You can just treat inequality signs just like an equality sign. Just remember that when you divide by a negative number, you must invert the equality sign, i.e:

\[ -3x \leq 2 \]
\[ \frac{-3x \leq 2}{-3} \rightarrow x \geq \frac{-2}{3} \]

Answer 6

thanks did it make a difference about the 6.0 vs0.6?

Answer 7

Im sorry, i don't follow. Could you rephrase the question?

Answer 8

oh you ask if the the 6 was on the right side of the problem it was written 0.6

Answer 9

got time for another one?

Answer 10

i asked abot the right hand side, not the left side. On the left you have 0.6 x +8 and on the right you have 0x -5. And that 0 confuses me, why did you even write it?

And yes, show me the other one

Answer 11

soybean meal is 12% protein Cornmeal 6% protein. How many lbs of each should be mixed together in order to get 240 lbs mix that is 10% proteing Corn mealLBS? Soybean lbs?

Answer 12

Ok, I'm going to take a little time in order to write a full explanation.

Answer 13

Fitst write equations to reflect what you know, let x be the amount of soybean in pounds and y be the amount of cornmeal in pounds. Then the total amount of mixture is (let's call this equation 1):
\[x + y = 240\]
And the total protein percentage is (let's call this equation 2):
\[12x + 6y = 10(x+y)\]

Substitute equation 1 in equation 2 and divide the whole thing by 6 to make things easier
\[ \frac{12x + 6y = 10(240)} {6}\]
\[ \frac{12x}{6} + \frac{6y}{6} = \frac{2400} {6}\]
\[ 2x + y = 400\]

Solve this for y:
\[ y = 400 - 2x\]

Now substitute this in equation 1:
\[ (400 - 2x) + x = 240\]
\[ 400 - x = 240\]
\[ x = 400 - 240\]
\[ x = 160\]

Substitute the value back in equation 1:
\[(160) + y = 240 \]
\[ y = 240 -160 \]
\[ y = 80 \]

If you plug these values in equation 2 the equality must hold to check our results:

\[12(160) + 6(80) = 10(160 + 80)\]
\[2400 = 2400 \]

Answer 14

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