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x intercept for x^2+y^2+2x-2y-2=0
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this is a circle so there should be two of them
x-intercept where y = 0, so replace y by 0 and get a quadratic equation in x. solve and those will be your two solutions. step one is \[x^2+2x-2=0\] you good from there?
if not let me know
yeah thanks i should be good
yw
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