Question

x intercept for x^2+y^2+2x-2y-2=0

Answer 1

this is a circle so there should be two of them

Answer 2

x-intercept where y = 0, so replace y by 0 and get a quadratic equation in x. solve and those will be your two solutions.
step one is
\[x^2+2x-2=0\] you good from there?

Answer 3

if not let me know

Answer 4

yeah thanks i should be good

Answer 5

yw