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The planes x + 2y + z = −4 and 3x + 3y − z = 3 meet in a line. how do i find a vector equation for that line?
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solve for any 2 of the variables by eliminating the 3rd. The simplest of the possible answers can be solved by just adding the 2 equations resulting to: 4x + 5y = -1
find the normal vectors for the two planes...then compute the cross product for these two vectors. There resulting vector will be parallel to the equation of the line you want.
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