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Which of the following is the solution to the equation sqrt5^8n = 125^(n +3)
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Did u mean this? \[\sqrt{5^{8n}} = 125^{n+3}\]
the 8n is outside of the sqrt function, but the 125^(n+3) you entered looks right
\[\sqrt{5}^{8n}=125^{n+3}\]like this?
exactly!
\[\sqrt{5}^{8n}=125^{n+3}\]
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\[\sqrt{5}^2=5\], \[5^3=125\] so \[\sqrt{5}^6=125\] is a start
my choices are n = –9 n = 9 n = –3 n = 3
n = 9
opps...and also -9
put \[8n=6(n+3)\] amd solve for n
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n = 9
Thanks so much!
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