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Mathematics 8 Online
OpenStudy (anonymous):

Please help me understand this.

OpenStudy (anonymous):

There is nothing to understand?

OpenStudy (anonymous):

\[\frac{2}{x-1}+1 = \frac{2}{x ^{2}-x}\]

OpenStudy (anonymous):

Solve for x:

OpenStudy (anonymous):

I did this whole problem for you an hour ago. You didn't understand it?

OpenStudy (anonymous):

I know you tried to help me earlier Mathandphysics, but I didn't understand how you got the common denominator

OpenStudy (anonymous):

the common denominator is something that can be shared by all 3 denominators. So what does (x-1), x, and (x^2 - x) have in common?

OpenStudy (anonymous):

I tried to pull it from the left side and I keep getting (x-1)(x^2-x) as the common denominator

OpenStudy (anonymous):

they are all part of (x^2 - x) because x times (x - 1) will get you to that.

OpenStudy (anonymous):

(x-1) is already part of (x^2 - x) so you don't need it

OpenStudy (anonymous):

We could cheat...

OpenStudy (anonymous):

So you can just throw it out the window?

OpenStudy (anonymous):

you don't throw it out. it is INCLUDED INSIDE of (x^2 - x)

OpenStudy (anonymous):

Let's cheat

OpenStudy (anonymous):

Let's do the left side only

OpenStudy (anonymous):

ok which would be 2/x-1 + x-1/x-1 right?

OpenStudy (anonymous):

Yes, it's all over x-1

OpenStudy (anonymous):

but wouldn't leave you with just 2/x-1

OpenStudy (amistre64):

\[\frac{2(x)}{x-1}+1(x) = \frac{2(x)}{x ^{2}-x}\] \[\frac{2x}{x-1}+x = \frac{2x}{x-1}\]

OpenStudy (anonymous):

sat i think ur on the wrong question man :)

OpenStudy (anonymous):

Complicated it all again...

OpenStudy (anonymous):

fakshon look ..

OpenStudy (anonymous):

if you had 1/2 + 1/4 = 1/6 ... what would be the common denominator?

OpenStudy (amistre64):

i forgot to cancel my x on the right :) doh!!

OpenStudy (anonymous):

ok which would be 2/x-1 + x-1/x-1 right? ie 1+x/x-1

OpenStudy (anonymous):

Just follow along, OK...

OpenStudy (anonymous):

oh my page was messed up .. thats weird

OpenStudy (anonymous):

So now we have 1+x/x-1 = 2/x^2-x agreed?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Do u know how to cross multiply?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Go on then, do it

OpenStudy (anonymous):

can you cross multiply over an = sign? Never done that before.

OpenStudy (anonymous):

you HAVE to cross multiply across an equal sign

OpenStudy (anonymous):

ie a/b =c/d -> ad = bc

OpenStudy (anonymous):

I'll do it (1+x)(x^2-x) = 2(x-1) U follow?

OpenStudy (anonymous):

Yes? No?

OpenStudy (anonymous):

ok so x^3-1 = 2x-2

OpenStudy (anonymous):

U went to fast....

OpenStudy (anonymous):

x^2-x is equal to x(x-1), right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So you can cancel the left and right of x-1

OpenStudy (anonymous):

Leaving (1+x)x = 2

OpenStudy (anonymous):

so x = 2 not -2?

OpenStudy (anonymous):

or did I lose it, lol

OpenStudy (anonymous):

Now we expand (1+x)x = 2 -> x+x^2 = 2 which is a quadratic...

OpenStudy (anonymous):

hey estudier go to chat after ur done

OpenStudy (anonymous):

Quadratic factors as (x+2)(x-1) _> x= -2 or 1

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