Question

How do you simplify:
(2x^2+x-12) /(x^2-16)

Answer 1

I was trying to factor the top to see if anything in the top and bottom cancel but i'm not sure.

Answer 2

Okay

Answer 3

You have to use long division for this

Answer 4

im not sure how you do long divison with expressions

Answer 5

Hold on a second

Answer 6

http://www.wolframalpha.com/input/?i=solve%28%282x^2%2Bx-12%29+%2F%28x^2-16%29%2Cx%29

Answer 7

Actually, that is the wrong solution. It shouldn't be set to zero

Answer 8

Are you sure you have this written correctly? Double check

Answer 9

Hero)))

Answer 10

sure
yeah its correct: (2x^2 + x -12 )/ (x^2 - 16)

Answer 11

I send u an email)

Answer 12

to the gmail)))

Answer 13

Well, what do you have to do? Solve for x?

Answer 14

the question was just to simplify the expression

Answer 15

so i was trying to see if anything cancels in teh top or bottom

Answer 16

\[\frac{2x^2 +x - 12}{(x+4)(x-4)}\]

Answer 17

That's the best you can do

Answer 18

Okay Kina

Answer 19

i got up to that part...so there is nothing aafter taht?

Answer 20

No..

Answer 21

ok tahnks...can you help me with another simplify teh expression question?

Answer 22

If I can, lol.. sure.

Answer 23

thanx...Simplify : (1/x+h) - (1/x)

Answer 24

Make them have the same denominator.

Answer 25

so is teh lcd: x+h

Answer 26

No. You need to multiply the denominators, right? It would be x(x+h). Remember whatever you do to the bottom, you have to do to the top...

Answer 27

oh ok...lemme try it out

Answer 28

After I multiply teh top and bottom out i get (x-x+h) / (x+h)...so does that simplify into h/ x+h?

Answer 29

Hero, I got -h/x(x+h) ^^

Answer 30

yeah, that's right

Answer 31

Good job

Answer 32

I forgot the negative

Answer 33

@denebelbel can u show me how u got ur solution?

Answer 34

\[\left(\begin{matrix}1 \\ x+h\end{matrix}\right) - \left(\begin{matrix}1 \\ x\end{matrix}\right) = \left(\begin{matrix}x-(x+h) \\ x(x+h)\end{matrix}\right) = \left(\begin{matrix}x-x-h \\ x(x+h)\end{matrix}\right) = \left(\begin{matrix}-h \\ x(x+h)\end{matrix}\right)\]

Answer 35

I helped you with one of your other problems. No medal? Not fair, lol

Answer 36

I ll give both of you a medal =]

Answer 37

Okay

Answer 38

@ deneble and @hero tahnk u both for helping...i suck at math XD