Question

how do I solve the square root of x+2 -1 (-1 is outside the root) = square root of x-5 ?

Answer 1

so its \[\sqrt{x+2}-1=\sqrt{x-5}\]

Answer 2

yes!

Answer 3

not sure how to square the x+2 part to get the answer

Answer 4

x=14? I'm not sure because I haven't done this in a while..

Answer 5

\[\sqrt{x+2}-1=\sqrt{x-5}\]
\[\sqrt{x+2}^{2}-1^{2}=\sqrt{x-5}^{2}\]
x+2-1=x-5
x=6

Answer 6

x=14! thanks so much

Answer 7

question really fast. how did you square the x+2 side?

Answer 8

x=14? Okay, so what I did was plug in another variable in place of \[\sqrt{x+2}\].. So I made that equal y. Maybe that will be easier, then you solve it regularly, but remember to substitute \[\sqrt{x+2}\] in y.

Answer 9

oh okay! thanks so much!