Question

Determine the nature of solutions of the equation

x^2-3x+8=0

Answer 1

you need to check the discriminant - know what that is ?

Answer 2

no

Answer 3

are you familiar with the quadratic equation ?

Answer 4

use quadratic formula

Answer 5

no not at all.

Answer 6

ever seen this formula ?

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 7

http://en.wikipedia.org/wiki/Quadratic_equation

Answer 8

\[(-b \pm \sqrt{b^{2}-4ac})/2a\]

Answer 9

In general:

ax^2+bx+c=0

In your case:
a=1 (the coefficient of x^2)
b=-3 (coefficient of x)
c=8

Use these values and plug them into the discriminant (the thingy inside the square root).

\[\Delta=b^2-4ac\]

If the discriminant = 0, there is one real solution
If the discriminant > 0, there are two real solutions
If the discriminant < 0, there are no real solutions