Determine the nature of solutions of the equation

x^2-3x+8=0

Question

Determine the nature of solutions of the equation

x^2-3x+8=0

anonymous · Answer

you need to check the discriminant - know what that is ?

anonymous · Answer

no

anonymous · Answer

are you familiar with the quadratic equation ?

anonymous · Answer

use quadratic formula

anonymous · Answer

no not at all.

anonymous · Answer

ever seen this formula ?

$$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

anonymous · Answer

http://en.wikipedia.org/wiki/Quadratic_equation

anonymous · Answer

$$(-b \pm \sqrt{b^{2}-4ac})/2a$$

anonymous · Answer

In general:

ax^2+bx+c=0

In your case:
a=1 (the coefficient of x^2)
b=-3 (coefficient of x)
c=8

Use these values and plug them into the discriminant (the thingy inside the square root).

$$\Delta=b^2-4ac$$

If the discriminant = 0, there is one real solution
If the discriminant > 0, there are two real solutions
If the discriminant < 0, there are no real solutions