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Sqrt(2+sqrt(2+sqrt(2+........=
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let Sqrt(2+sqrt(2+sqrt(2+........ be x
then Sqrt(2+sqrt(2+sqrt(2+........=Sqrt(2+x)
x=\[\sqrt{2+x}\]
x^2 -x-2 = 0
Not x just sqrt2+x
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I never put an x...
wat??
U answered question already...
answer is 2 and -1
Answer is sqrt(2+x), that's it...
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answer is 2 and -1 is the answer to x= sqrt(2+x)
kkk
I don't do numbers...
2
oh i am a little late i see...
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already answered
I feel like a broken record...before you use the above 'trick' you need to establish that the process converges.
We are all Euler here..:-)
which in this case means you have only to give an upper bound, since it is increasing. i pick 2
Lim sqrt(a+b(sqrt(a+b sqrt.....) = (b + sqrt(b^2 +4a))/2 (a, b>0)
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There is only one Euler ...The master of us all ;)
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