Given that the volume of water a pipe 500 m long with a volume of 98.187m^3, is 98187 liters. if water flows through the pipe at 0.8m/s, how many liters will flow through the pipe in 1 hour?? pls show working if possible, thanks :)
The tricky part is that 0.8m/s is telling you the velocity at which water is coming out, to know how much water is coming out in Volume you need to determine the volumetric flow rate (units m^3/time). The missing piece of information is the area of the pipe. Liters in one hour = VolumetricFlow * time VolumetricFlow = PipeArea * 0.8 m/s * 3600 s/h = time = 1 hour Assuming the pipe is a cylinder PipeVolume = PipeArea * length PipeArea = PipeVolume/length = 98.187 m^3/500m = 0.1964 m^2 Substitution the pipe area in the equation for VolumetricFlow Liters in one hour = 565.63 m^3 The attached file has details of the calculation.
oh wow touchy maths how did you do that
but i didn't give you the entire info. the diameter is 0.5m :P
you can calculate that no need for that
is there any simpler wayy??
I say find the cross section are pir^2
that is 0.196375.
then calculate time to travel along the pipe with the water's speed
end to end
ah calculate I don't like calculations I need your support
500 m is distance and speed is .8m/s
ah no need for calculations time is 625 seconds
now in 625 second a volume of 98.something will flow through the pipe
98187 litres
I find it easier to work these physics problems if you start by defining the solution using words and work your way back. The solution is: Volume = Flow * time of flow time = 1 hour = 60 minutes = 3600 seconds ...
ah there are 3600 seconds in an hour
oh, wait, i think i got it :) 1liter can flow in 0.174 hours, so x liters will flow in 1 hour, and cross multiply. btw, touchymath, that, was, AMAZING!!
Glad I could help! : )
and the volume would be 5.76 l, right?? yay !!!
ah no I think you got wrong somewhere
Actually, there are 1000 liters in one m^3, so the answer is 565.63 (meters^3) = 565 630 liters
3600 ------ x 98187 = 565557.12 litres 625
ah that is what I get well both are equivalent
anyways, whats the formula for finding the length of a line on a graph?
\[d = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}\]
aha!! i was right!!! thanks a LOT!!!! :D
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