Question

Factor by grouping.. I need help refreashing my memory. 3x^3-x^2+18x-6

Answer 1

Well I can't help but notice that \(3\cdot 6 = 18\)

So my guess is you'll want to start with something like:
\[(3x^3 + 18x) - (x^2 + 6)\]

Answer 2

ok now im still alittle confused on the next step

Answer 3

Factor out a 3 from the terms in the first set of parens.

Answer 4

3(x^3+18x)

Answer 5

You have to factor it out of both terms.

Answer 6

3(x^3+6x)

Answer 7

Now factor an x out also.

Answer 8

3x(x^2+6)

Answer 9

Ok so now you have \[3x(x^2 + 6) - (x^2 + 6)\]

Answer 10

So factor an \((x^2 + 6)\) from each term in your difference.

Answer 11

answer is 3x(x^2+6)

Answer 12

no

Answer 13

sorry

Answer 14

Im unsure

Answer 15

Lets say you have:

3xa - a

How would you factor out an a from each of those?

Answer 16

Im not sure

Answer 17

How did you factor an x from x^3 + 6x ?

Answer 18

use synthetic division

Answer 19

is my answer 3x(X^2+6)^2