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OpenStudy (ksaimouli):
f(x)=under the root x+3 what is the range and domain?
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OpenStudy (anonymous):
do you mean f(x) = sqrt(x+3) ?
OpenStudy (ksaimouli):
determine the domaine and rage
OpenStudy (ksaimouli):
\[\sqrt{?}\]+3
OpenStudy (ksaimouli):
under the root of x+3
OpenStudy (ksaimouli):
the root will be for both
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OpenStudy (anonymous):
domain is (-3,INF)
OpenStudy (anonymous):
range is [0,INF)
sorry domain is [-3,INF) '[' means including the value
OpenStudy (ksaimouli):
how
OpenStudy (ksaimouli):
u got the ans
OpenStudy (ksaimouli):
plz explain in detaile
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OpenStudy (anonymous):
well - there is no real number which is the square root of a negative - therefore the lowest possible value of x+ 3 is zero.
x+ 3 is zero when x = -3
OpenStudy (ksaimouli):
then how u got -3,inf
OpenStudy (anonymous):
well the domain is all the possible values of x - -3 is lowest value but values above it go up to infinity
OpenStudy (anonymous):
the range is all the possible values of f(x) lowest possible is sqrt(-3+3) = 0 and highest is infinity
OpenStudy (anonymous):
[-3,INF) means all values of x from -3 to infinity
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OpenStudy (ksaimouli):
ok thanks
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