25^(1/2)=5 convert to logarithmic equation log(25)___=___
log(25)=2 x log(5)
when you log something it brings down the exponent such that 1/2 x log (25) =log (5)
\[b^x=y\iff \log_b(y)=x\]
multiply both sides by 2 and you get log (25)=2 log(5)
i think you are supposed to fill in the blanks as follows \[\log_{25}(5)=\frac{1}{2}\]
that's the format I was looking for. thanks you both:)
yw
btw if you do these often you should get used to going from \[b^x=y\] to \[\log_b(y)=x\] quickly and with ease
great! that's useful for sure
I'll need to practice that..
\[log_b(a) = k \iff b^k = a\] The \(\iff\) symbol means you can go back and forth from the left side to the right. Each side means the same thing as the other.
basically the same as what an equals sign says, no?
Not quite.
You cannot say that \[log_b(a) = k = b^k = a\] Because \(log_b(a) \) doesn't equal \(a\)
okay, I'm beginning to see this...
\[2^4=16\iff \log_2(16)=4\] \[\log_{10}(1000000)=6\iff 10^x=1000000\] \[\log(.01)=-2\iff 10^{-2}=.01\] \[8^{\frac{2}{3}}=4\iff \log_8(4)=\frac{2}{3}\]
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