Question

evlutate :( (1-u)+1)^2

Answer 1

this is part of an intergral i am doing

Answer 2

intergral: (x+1)^2(1-x)^5

Answer 3

isn't this
\[(2-u)^2\]?

Answer 4

i choose u as being (1-x) and then reworte x in terms of u

Answer 5

but x=1-u

Answer 6

then i subs it in to (x+1)^2

Answer 7

satellite help meeee

Answer 8

i think that is just swapping apples for oranges

Answer 9

so, then how would i go about solving this, i got no clue

Answer 10

do i just have to expand

Answer 11

think best bet is to grind it til you find it
multiply all that crap out, combine like terms, integrate term by term, cheat and uses a machine

Answer 12

but, there has to be another way i am not seeing, cause this is a problem from the solving integrals by sub chp

Answer 13

here
http://www.wolframalpha.com/input/?i=integrate++%28x%2B1%29^2%281-x%29^5

Answer 14

after i expand each term: (x+1)^2 and (1-x)^5 i have to multiply them together right?

Answer 15

\[u=x+1\]
\[1-x=1-(u+1)=2-u\] and now you have
\[u^2(2-u)^5 which buys you nothing

Answer 16

let me think before i speak

Answer 17

zarkon?

Answer 18

sate

Answer 19

how about u=1-x

that would make multiplying it out a little easier

Answer 20

I don't see a really nice way at first glance

Answer 21

man , but in the end i will still have to sub back in that 1-x and multiply it out

Answer 22

I would sub back 1-x but I wouldn't multiply it all out

Answer 23

so i would get: (x^2+2x+1)(u)^5

Answer 24

oh yes zarkon is as usual right. it is just a question of figuring out the cheapest way to do the multiplication

Answer 25

\[u=1-x\]
\[x+1=2-u\] and then
\[(2-u)^2u^5=(4-4u+u^2)u^5=4u^5-4u^6+u^7\] but this doesn't really help either does it because you still have to either integrate and then expand, or expand and then integrate. sorry

Answer 26

how did you get that: x+1=2-u

Answer 27

what is wrong with integrating ...substituting back 1-x and then leaving as it is ...it will be the anti derivative.

Answer 28

sure why not. everything will just be in terms of 1- x instead of x

Answer 29

\[u=1-x\]
\[x=1-u\]
\[x+1=1-u+1=2-u\] is the answer to your question

Answer 30

got you homie

Answer 31

let me get down to work