If $ 2500 is invested in an account that pays interest compounded continuously, how long will it take to grow to $ 5000 at 3%? Round to the nearest tenth. Can someone please show meall the steps to solve.
Use the formula A= Pe^rt
P=2500 r=.03 A=5000
your job is to solve \[5000=2500e^{.03t}\] for t. can you do that? first step is divide by 2500 second is to take the log third is to divide by .03
i can write it if you like
did you get it?
how long does it take to double :)
yes please show me, not sure what log third is?
ln(2)/r i beleive
ok start with dividing by 2500 and get \[2=e^{.03t}\] take the log get \[\ln(2)=.03t\] and then divide by .03 get \[t=\frac{\ln(2)}{.03}\] then a calculator
"take the log" is shorthand for "write in equivalent logarithmic form"
ln(n-tuple)/r is the basic formula
what amistre said. point is that the initial amount was half the final amount, so you were answering the question "how long before your money doubles?"
if you invest $2,500 and amistre invests 10, 000,000 and i invest $12.50 the doubling time is still the same
ok I think i got it. thanks
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