Question

Find the equation of a circle that has a diameter with endpoints at (0, 4) and (-3, 1)
then tell me how you did it :)

Answer 1

circle with a diameter? no way

Answer 2

lol .... determine mid point

Answer 3

What's the midpoint formual again :D?

Answer 4

hlafway

Answer 5

halfway

Answer 6

add the points and divide by 2

Answer 7

uh.. okay

Answer 8

(0,4) + (-3,1)?

Answer 9

(0, 4)
(-3, 1)
------
(-3 , 5) /2 = (-3/2, 5/2)

Answer 10

for example; whats halfway between 6 and 8?

6+8 = 14, /2 = 7 right?

Answer 11

sure
now that I have that, what can I do with it?

Answer 12

use it for the center :)

Answer 13

now determine the distance between your points by subtracting them and pythaging it

Answer 14

(0, 4)
-(-3, 1)
-------
3 , 3 ; well, thats good; its just 3 sqrt(2)

Answer 15

pythaging it?

Answer 16

isn't their an easier, more algebraic way of finding the equation here?

Answer 17

yeah; sqrt(x^2 + y^2) ... the pythag thrm

Answer 18

there* wow

Answer 19

yeah, get someone else to do it :)

Answer 20

but no, this is the nuts and bolts of it

Answer 21

since we now the distance from point to point; split it in half to determine the radius

Answer 22

and put it all together now:

(x+(3/2))^2 + (y-(5/2))^2 = (3sqrt(2)/2)^2