Simplify: log x + log(x-3) = 1

Question

anonymous · Answer

Sorry teh question was to solve for x

anonymous · Answer

$$\log(x(x-3))=1$$ is a start

myininaya · Answer

here's a start
$$\log|(x(x-3))|=\log(10)$$

anonymous · Answer

then write in equivalent exponential form and write 
$$x(x-3)=10$$ etc

anonymous · Answer

couldn't help yourself could you?

myininaya · Answer

i need to go to sleep for real

anonymous · Answer

simplify to log x^2-3x = 1

automatic base 10, so 10=x^2-3x

so $$x ^{2}-3x-10=0$$

solve for x

(x-5)(x+2)=0

x=5, -2

anonymous · Answer

yeah those early morning anti derivatives come at you hard

myininaya · Answer

-2 won't work

myininaya · Answer

just x=5

anonymous · Answer

and don't forget to discard -2 because you cannot take the log of a negative number

anonymous · Answer

what myininaya said

anonymous · Answer

yes, that's true. forgot about that, sorry

myininaya · Answer

satellite when i put my mouse clicker over your picture it makes it look like your bicycle is going

myininaya · Answer

math help you have any questions?

anonymous · Answer

how did you start off with logx^2-3x = 1...what log rule is taht

myininaya · Answer

we have log(x)+log(x-3) right?
on the left hand side?
we can use ln|x(x-3)|
but that equals ln|x(x)-x(3)|=ln|x^2-3x|

myininaya · Answer

see i use the distributive property inside the ln function

anonymous · Answer

oh i see..tahts makes sense now.....Can one of you help me with another solve for x problem?