Question

Find the vertex
f(x)= 3x^2-18x+3
please help me. Awards will be given

Answer 1

use the all mighty formula
\[x=
-\frac{b}{2a}\] to find the first coordinate

Answer 2

in this case
\[a=3,b=-18\] so
\[-\frac{b}{2a}=-\frac{-18}{2\times3}=3\]

Answer 3

that is the first coordinate and the second coordinate is what you get when you replace x by 3. you get
\[3\times 3^2-18\times 3+3=27-54+3=-27+3=-24\] check my arithmetic because it is late

Answer 4

also because i didn't really compute. as soon as i saw 27 i knew the next one would be -54. always works that way

Answer 5

vertex is (3,-24) unless i messed up

Answer 6

so (3,-24) ? and that would make it a maximum right?

Answer 7

heck no

Answer 8

this is a parabola that faces up. no max, but a min

Answer 9

the minimum value is -24

Answer 10

Ah I got it mixed up!

Answer 11

I always do that with the minimum maximum.