determine the value of h such that the matrix is the augmented matrix of a consistent linear system. row 1: 1 -1 4 row 2: -2 3 h
ok step 1: row 2 -> add to 2*row 1 1 -1 4 0 1 (h+8) maybe im doing this wrong but it seems like h could be any real number and this would still be a consistent system ??
well thats the answer. and now I know why. Thank you very much. Just for a bit more detail. When solving something like this, what should I do?
think of it like elimination use row operations to get all zeroes below the diagonal of the matrix if you end up with all 1's in the diagonal, there is 1 solution, consistent system if a row ends up with all zeroes, dependent system, infinite solutions if a row ends up with all zeroes except for last column, No solution, inconsistent system
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