Question

Simplify: e^(1+lnx)

Answer 1

e^(1+lnx) = e. e^lnx =e.x because (e^lnx =x)

Answer 2

i dont quite understand

Answer 3

I'm not too familiar with e and ln, but I can help.

e^(1+lnx)
e^1 x e^lnx

Does e and ln now cancel eachother off and your left with:
e^1 x 1^x?
I hope this helped a little, even though I couldn't help much.

Answer 4

hey @chaise: can u tell me if this eq. can b simplified any more?

Answer 5

I couldn't be too sure. I'm not too familiar with logarithims. I wish I was. All I know is that if you have
x^(m+n) it can be written as x^m x x^n

Answer 6

\[(2x ^{2}+x-12) / (x ^{2}-16)\]

\[(2x ^{2}+x-12) / (x+4) (x-4)\]

Answer 7

is teh top factorable

Answer 8

No.

Answer 9

so its simplifed to that extent?

Answer 10

sabrina any point was not clear with logarithm?

Answer 11

yeah i didnt quite understand the explanation or reasoning as to y the asnwer is equal to e.

Answer 12

can u explain it raheen?

Answer 13

ok

Answer 14

first let me remind you with this rule a^n *a^m = a^(n+M)

Answer 15

got that?

Answer 16

2^3*2^4 = 2^(3+4) = 2^7 as a numberiv example

Answer 17

now for 2^(3+4) can work in reverse too i,e 2^(3+4) =2^3 *2^4

Answer 18

the same we work on e^(1+lnx)

Answer 19

i.e e^(1+lnx) = e^1 * e^lnx

Answer 20

now e^1 =e

Answer 21

and every e to the power of ln(x) would equal only x

Answer 22

so e^lnx =x ( as if e to the power of ln would cancel each other

Answer 23

is that ok with you?

Answer 24

omg this makes so much more sense now with teh example. THANK YOU! =)

Answer 25

:)Most Welcome

Answer 26

I know without making it simple to to would still show some difficulty

Answer 27

EXACTLY...im a visual learner so if someone jsut skips alot of steps i am soo lost and confused. thanks for your time.

Answer 28

not at all

Answer 29

do u mind if i ask u some questions i dont understand?

Answer 30

ok

Answer 31

can u post them in another thread

Answer 32

sure...ill post it now

Answer 33

or u prefer here

Answer 34

i dont mind...whatever you want...ur teh oen helping me

Answer 35

ok it's your choice

Answer 36

then post it here

Answer 37

ill post another thread and send u the link

Answer 38

oh ok then

Answer 39

I need to find teh domain n ranges of some equatiosn except i find it hard to know what to exaclty put as the domains adn ranges

Answer 40

1) \[\left[ x+3 \right] - 2\]

Answer 41

is that an absolute value ?

Answer 42

can you write the instructions

Answer 43

oh sorry yes tahts supposed to be an absolute value and the instructions are: to write the domain and range of the functions.

Answer 44

\[\left| x+3 \right| = x+3 \] if x>= -3

Answer 45

oh
you need only domain & range then domain is Real Number Set

Answer 46

Range is the y values so range = [-2,infinity)

Answer 47

what else?

Answer 48

y=e^x

Answer 49

same thing: domain n range

Answer 50

y=e^x , this an exponential function where the domain would be the real number set

Answer 51

the rang is (0,infinity)

Answer 52

Why is the 12 there?

Answer 53

where you find 12?

Answer 54

Oops, wrong convo! Open Study lags too much!

Answer 55

for the exponential & logarithem function you better memorize the shape of them through their graphs here

Answer 56

yes lags is so bad here

Answer 57

following?

Answer 58

yes

Answer 59

since y=lnx is teh inverse of y=e^x, is the domain and rain jsut switched?

Answer 60

Exactly sabrina

Answer 61

cool...how about shapes liek circles? they dont really have an ending nor start. For example x^2+y^2=25?

Answer 62

what would teh domain and range for that be?

Answer 63

the circle is not a function , it's an equation

Answer 64

so there is no domain or range for that?

Answer 65

domain and range are only when we are talking about a function or a relation but not with an equation

Answer 66

i thought there would be one b.c you can graph a circle.

Answer 67

do mean that you thought that every graph couldd have a domain and range?

Answer 68

I wish things got better now with you regarding wat you posted

Answer 69

yes. thank you very much. And yes i thought anything tath was graphed had a domain and range.

Answer 70

tahnk you for your time and effort.

Answer 71

oh ,that is misconception

Answer 72

more welcome ,any time sabrina

Answer 73

you are honestly a life saver. it's hard to do math when there is no skool since i cant ask anyone. this site is truly amazing! =) thanks to people like you.

Answer 74

sure, you are righonly some people they are doing a good communication is helping others

Answer 75

sabrina do you have any idea about sites like this

Answer 76

as in my opinion about the site?

Answer 77

or if i knew taht sites like these existed?

Answer 78

yes, I'm asking if you know some other exciting

Answer 79

actually I like to have an idea about even your math books , are they online found

Answer 80

im taking ap calculus next year but i haven't received the book yet.the book i had for pre-calulus and the books are not found online

Answer 81

i wish they did. most of our math textbooks just come with a CD-rom.