Question

Simplify: (4xy^-2) / [ 12x^(-1/3) y^5]
I'll write the equation nicer w/ the equation box

Answer 1

\[(4xy ^{-2}) / (12x ^{-1/3}y ^{-5})\]

Answer 2

4xy^-2 = 4/xy^2
12x^-(1/3) = 12/cubroot(12x)
y^-5 = 1/y^5

Can you do the rest?

Answer 3

lemem try

Answer 4

wait what am i supposed to do after your step?

Answer 5

Chaise, I think it is
\[\left(\begin{matrix}4x y^{-2} \\ 12x ^{-1/3}y ^{-5}\end{matrix}\right) = \left(\begin{matrix}4x ^{1}x ^{1/3}y ^{5} \\ 12y ^{2}\end{matrix}\right)\]

The x doesn't go to the denominator, right?

Answer 6

so whose correct??

Answer 7

@denebel is this ur final answer

Answer 8

i dont think atht is fully simplified

Answer 9

No that is not the final answer. You need to simplify it some more. For instance, with the x, there are 2 x's: one to the first power, and the other to the 1/3 power. Do you remember what you can do with them?

Answer 10

ur supposed to add them right?

Answer 11

can you show out teh final solution and the steps?

Answer 12

Yes, you are supposed to add them. You are almost there... Then you can simplify the 4/12 right?

Answer 13

1/3

Answer 14

Okay... now put it all together.

Answer 15

I got : \[(x ^{4/3}y ^{5}) / (12y ^{2})\]

is taht correct

Answer 16

Why is the 12 there?

Answer 17

oh i meant 3y^2

Answer 18

That is correct.

Answer 19

is teh rest correct? btw do we not have to do anything to the x^(4/3)? is taht ok to have it liek taht

Answer 20

\[(x ^{4/3}y ^{3})/3\]

Answer 21

Oh, yes, Arnab09 is correct, we forgot about the y.

Answer 22

Basically you are just subtracting the exponents when you divide variables.