Question

lim (x^2-1)/(x-1)
x->1

Answer 1

I don't think it is infinite.

Answer 2

answer in the back of the book is 2 can you explain

Answer 3

(x^2-1) = (x+1)(x-1)

(x+1)(x-1)/(x-1)

The x-1's cancel off. Your left with x+1
Sub in your value.

2 is the answer

Answer 4

The limit is 2.

Answer 5

limit is 2...

Answer 6

The answer is 2. You factor the numerator so it is (x+1)(x-1)... (x-1) cancels with the (x-1) in the denominator. As x approaches closer to 1, the y will be 2. Therefore, the limit is 2.

Answer 7

Okay I didn't factor the numerater and was getting 0

Answer 8

if you substitute and the answer results to 0/0, you can factor out..

Answer 9

do you always factor if there is a exponent

Answer 10

You factor if you can... lol

Answer 11

you can also derivate (x^2 - 1) and (x - 1) getting lim 2x/1, x -> 1

Answer 12

you can try
L'hopitals rule will work here as well
\[\frac{(d/dx) x^{2}-1}{(d/dx) x-1} = 2x\]

Answer 13

Thanks guys appreciate it