Question

find the integers,given the following
sum is-15 product is 50

Answer 1

x+y=-15
xy=50
x=-10
y=-15

Answer 2

y=-5

Answer 3

sorry..hehehehhe

Answer 4

x=-10
y=-5

Answer 5

\[x+y=-15, xy=50. hence, x-y=\sqrt{(x+y)^{2}-4xy}=5. then you will get the terms as -10 and -5\]

Answer 6

you could not get it?

Answer 7

ok, if you can't get it, at least give me a medal, please. i assure you, i answered the question correct

Answer 8

ok!!!!.. ^^

Answer 9

eq1.
x + y= -15

eq2.
xy = 50

manipulate eq1
x=-15-y (eq3)

substitute eq 3 to eq2
(-15-y)y=50
\[-15y-y^{2}=50\]
transpose
\[50+15y+y^2=0\]
\[y ^{2}+15y+50=0\]
(x+10)(x+5)
x+10=0
x=-10

x+5=0
x=-5

Answer 10

Oh! Frightening!!!!!!!

Answer 11

sorry..in the last part...its not x, its y....sorry...hehehehhe

Answer 12

that's alright. assume that x=y and y=x :)